Please Help; Algebra2 Trig Course

[Booba]

Please help me with this problem:
solve for x: 27^x+1=81^x

 

[stapel]

Please help me with this problem:
solve for x: 27^x+1=81^x

As written, the above means:

. . . . .\(\displaystyle 27^x\, +\, 1\, =\, 81^x\)

Did you perhaps actually mean to say "27^(x+1)" for the left-hand side, so the equation is actually like the below?

. . . . .\(\displaystyle 27^{x\, +\, 1}\, =\, 81^x\)

Thank you!

 

[Deleted member 4993]

81^x - 27^x -1 = 0

Newton says x = 0.293356099595198

 

[Quaid]

Did you perhaps actually mean to say "27^(x+1)" for the left-hand side

Oooh, that's a good guess, Stapel. That makes more sense.