Results 1 to 6 of 6

Thread: Determine diameter of a circle from a straight line

  1. #1

    Determine diameter of a circle from a straight line

    I'm sure this is a basic high school problem, but I don't know the answer, hence I am here. I need to bend a straight pipe into a circle and need to know how to figure out how long the pipe needs to be to create a 4 foot diameter circle. Any help would be greatly appreciated.

  2. #2
    Elite Member
    Join Date
    Jan 2005
    Posts
    7,505
    Quote Originally Posted by rightbraincreative View Post
    I'm sure this is a basic high school problem, but I don't know the answer, hence I am here. I need to bend a straight pipe into a circle and need to know how to figure out how long the pipe needs to be to create a 4 foot diameter circle. Any help would be greatly appreciated.
    The circumference of a circle is [tex]\pi\cdot D[/tex]. A good approximation is "three times around as it is across"
    [tex]\pi\approx 3.1415[/tex].
    “A professor is someone who talks in someone else’s sleep”
    W.H. Auden

  3. #3
    Senior Member
    Join Date
    Aug 2010
    Posts
    2,340
    Quote Originally Posted by pka View Post
    The circumference of a circle is [tex]\pi\cdot D[/tex]. A good approximation is "three times around as it is across"
    [tex]\pi\approx 3.1415[/tex].
    As [tex]\pi \ [/tex] = 3.141592..., the rounded value of [tex] \ \pi \ \ = \ \ 3.1416 \ \ [/tex] to four decimal places.

  4. #4
    Quote Originally Posted by pka View Post
    The circumference of a circle is [tex]\pi\cdot D[/tex]. A good approximation is "three times around as it is across"
    [tex]\pi\approx 3.1415[/tex].
    So, without getting into too many decimal points, my 4 foot diameter circle can be created by multiplying pi times the diameter I need. 3.14 x 4= 12.56. My pipe needs to be roughly 12 and a half feet to make a four foot hoop. Thank you all for your expertise. This will help me finish an art project I am working on. I knew pi was involved in the equation, but not how. I guess I should have paid more attention in math classes and less attention to art. But, in the end, art is what pays my bills each month.

  5. #5
    Elite Member stapel's Avatar
    Join Date
    Feb 2004
    Posts
    15,923

    Cool

    It should be noted, of course, that these are "ideal" mathematical computations on "ideal" geometrical objects. When dealing with real-world physical objects, allowances usually need to be made for width, depth, cutting losses, etc. For instance, if the stated desired diameter refers to the inner diameter of the physical object, then allowances must be made for stretching of the material, along with the depth of the material (diameter of the pipe, perhaps?), with the computations adjusted to account for the fact that a pipe cut to form the desired circle on the inner edge may have a gap on the outer edge. And crushing or crumpling may reduce the expected inner measure, after bending, as well.

  6. #6
    Quote Originally Posted by stapel View Post
    It should be noted, of course, that these are "ideal" mathematical computations on "ideal" geometrical objects. When dealing with real-world physical objects, allowances usually need to be made for width, depth, cutting losses, etc. For instance, if the stated desired diameter refers to the inner diameter of the physical object, then allowances must be made for stretching of the material, along with the depth of the material (diameter of the pipe, perhaps?), with the computations adjusted to account for the fact that a pipe cut to form the desired circle on the inner edge may have a gap on the outer edge. And crushing or crumpling may reduce the expected inner measure, after bending, as well.
    Thank you for the additional thoughts. Yes, these are conditions I need to factor in to my design.

Tags for this Thread

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •