I am working on a question to find the coordinates of the point(s) along a curve at which it is horizontal. The equation of the curve is y = (cosx)/(2+sinx), and 0 </= x </= 2pi.
I calculated the derivative to be y' = ((2+sinx)(-sinx) - (cosx)^2) / (2+sinx)^2. And to find the points at which the curve is horizontal, I set the derivative = 0, and tried to solve for x. But I cant seem to isolate x, I am wondering if there is something I am missing, or an alternate method I should be using? Any help would be appreciated.
I calculated the derivative to be y' = ((2+sinx)(-sinx) - (cosx)^2) / (2+sinx)^2. And to find the points at which the curve is horizontal, I set the derivative = 0, and tried to solve for x. But I cant seem to isolate x, I am wondering if there is something I am missing, or an alternate method I should be using? Any help would be appreciated.