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Thread: Solving Algebraic Expressions with too many variables........ Help!!!!

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    Junior Member lillybeth's Avatar
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    Question Solving Algebraic Expressions with too many variables........ Help!!!!

    Hey guys!! I'm having a little trouble understanding my algebra 1 homework, so any help will be greatly appreciated!!!

    I have some problems that look like this:

    SOLVE
    6(b+7)=b-4



    I don't understand how to solve this when there is a variable on both sides of the equation.....

    Please help!!!
    Thanks!!
    "If you believe in something, believe in it all the way, implicitly and unquestionably." - Walt Disney

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    So you do know that 6(b+ 7)= 6b+ 42? Your equation is the same as 6b+ 42= b- 4. What do you get if you subtract b from both sides? What do yu get if you subtract 42 from both sides.

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    Junior Member lillybeth's Avatar
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    Quote Originally Posted by HallsofIvy View Post
    So you do know that 6(b+ 7)= 6b+ 42? Your equation is the same as 6b+ 42= b- 4. What do you get if you subtract b from both sides? What do yu get if you subtract 42 from both sides.
    If you subtract b from both sides i think you get 6+42=-4, and then u subtract 42 and get 6=-44.

    Is that the answer??
    But six is not equal to negative forty-four.
    ??
    Last edited by lillybeth; 09-27-2014 at 05:45 PM.
    "If you believe in something, believe in it all the way, implicitly and unquestionably." - Walt Disney

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    Junior Member lillybeth's Avatar
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    Quote Originally Posted by lillybeth View Post
    If you subtract b from both sides i think you get 6+42=-4, and then u subtract 42 and get 6=-44.

    Is that the answer??
    But six is not equal to negative forty-four.
    ??
    Actually, I think it did it wrong...

    would it be 6b=-44?

    I'm not exactly certain, neither one makes much sense to me, would the answer be a decimal? b= -7.2???
    "If you believe in something, believe in it all the way, implicitly and unquestionably." - Walt Disney

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    Quote Originally Posted by lillybeth View Post
    Hey guys!! I'm having a little trouble understanding my algebra 1 homework, so any help will be greatly appreciated!!!

    I have some problems that look like this:

    SOLVE
    6(b+7)=b-4



    I don't understand how to solve this when there is a variable on both sides of the equation.....

    Please help!!!
    Thanks!!
    6b + 42 = b - 4

    6b + 42 - b = b - 4 - b (subtract b from both sides)

    6b - b + 42 = b - b - 4

    5b + 42 = -4

    5b + 42 - 42 = -4 - 42 (subtract 42 from both sides)

    5b = - (42 + 4)

    5b = -46

    [tex]\dfrac{5b}{5} \ = \ \dfrac{-46}{5} [/tex] ... (divide both sides by 5)

    b = -9.2

    Lillybeth - I strongly suggest that you talk to your teacher and get this type of problems "totally right" - without any confusion.

    Also go to:

    http://www.purplemath.com/modules/solvelin.htm

    and work through the example problems there.
    “... mathematics is only the art of saying the same thing in different words” - B. Russell

  6. #6
    Junior Member lillybeth's Avatar
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    Quote Originally Posted by Subhotosh Khan View Post
    6b + 42 = b - 4

    6b + 42 - b = b - 4 - b (subtract b from both sides)

    6b - b + 42 = b - b - 4

    5b + 42 = -4

    5b + 42 - 42 = -4 - 42 (subtract 42 from both sides)

    5b = - (42 + 4)

    5b = -46

    [tex]\dfrac{5b}{5} \ = \ \dfrac{-46}{5} [/tex] ... (divide both sides by 5)

    b = -9.2

    Lillybeth - I strongly suggest that you talk to your teacher and get this type of problems "totally right" - without any confusion.

    Also go to:

    http://www.purplemath.com/modules/solvelin.htm

    and work through the example problems there.




    Oh, okay I get it now.

    Thankyou so much for your help!!!!!!!!!!!
    "If you believe in something, believe in it all the way, implicitly and unquestionably." - Walt Disney

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