On which interval is the graph of f(x)=4x^(3/2) - 3x^2 both concave down and increasing?
A. (0,1) B. (0, .5) C. (0, .25) D. (.25, .5) E. (.25, 1)
I found f'(x)=6x^1/2 - 6x
and f''(x)=3x^-1/2 - 6
I set f'' equal to zero and got x=.25
Also, I believe it is undefined at 0?
Would the answer be C? I'm not sure where to go from here if it's not.
A. (0,1) B. (0, .5) C. (0, .25) D. (.25, .5) E. (.25, 1)
I found f'(x)=6x^1/2 - 6x
and f''(x)=3x^-1/2 - 6
I set f'' equal to zero and got x=.25
Also, I believe it is undefined at 0?
Would the answer be C? I'm not sure where to go from here if it's not.