When taking the derivative of y = (x2/3 + 2e-9x)6
Its a chain rule derivative so the first part is 6 (x2/3 + 2e-9x)5
The first part of the inner function is a simple power rule (2/3) x-1/3
Im stuck on the second part, the x is an exponent so I think to use the exponent rule.
Applying dy/dx bx = bxln (b) I get 2e9x ln (2e). ln (2e) = 1.693 so I get 3.39e9x
The answer is -18-9x.
Where did I go wrong?
Thanks!
Its a chain rule derivative so the first part is 6 (x2/3 + 2e-9x)5
The first part of the inner function is a simple power rule (2/3) x-1/3
Im stuck on the second part, the x is an exponent so I think to use the exponent rule.
Applying dy/dx bx = bxln (b) I get 2e9x ln (2e). ln (2e) = 1.693 so I get 3.39e9x
The answer is -18-9x.
Where did I go wrong?
Thanks!