Inequality equation help

on3winyoureyes

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Jan 20, 2015
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x3>=3x
find the domain and range and write in interval notation

for this equation, do we subtract the 3x and make the equation equal to zero? I'm just not quite sure how to solve it.
 
x3>=3x
find the domain and range and write in interval notation

for this equation, do we subtract the 3x and make the equation equal to zero? I'm just not quite sure how to solve it.
What are your thoughts?

If you are stuck at the beginning tell us and we'll start with the definitions.

Please share your work with us ... even if you know it is wrong

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...Before-Posting


Hint:

x^3 >= 3x

x^3 - 3x >= 0

x(x + √3)(x - √3) >= 0

Now continue.....
 
x3>=3x
find the domain and range and write in interval notation
This is not a function, so "domain" and "range" make very little sense, in context. Are you maybe supposed to "find the solution" and write that in interval notation?

Also, you posted this to "Calculus", so you must be expected to use something other than just algebra for this. Please provide that information. Thank you! ;)
 
Yes, you can subtract 3x from both sides to get \(\displaystyle x^3- 3x= x(x^2- 1)\ge 0\).

Now, if the product of two numbers is positive, what must be true of the two numbers?
 
An Inequality equation??
​Is that an oxymoron?
 
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