y = x((x^m)+1). If m is odd, then x=-1 is a root of x((x^m) + 1). Also x =0 is a root of x((x^m) + 1). Then this function is not 1-1 and hence has no inverse.hello there,
I'm a newbie here. Im an engineering student and I really need your help for my problem.
I have an equation and need to find the inverse function.
y=xm+1+x
tqvm
y = x((x^m)+1). If m is odd, then x=-1 is a root of x((x^m) + 1). Also x =0 is a root of x((x^m) + 1). Then this function is not 1-1 and hence has no inverse.
Is there any information about m??
You've shown one m-value for which it appears there may be an inverse function. The other poster showed an m-value for this there definitely is not an inverse function. Thus, there can be no generalized inverse function in terms of m.the m is variable positive numbers.
You've shown one m-value for which it appears there may be an inverse function. The other poster showed an m-value for this there definitely is not an inverse function. Thus, there can be no generalized inverse function in terms of m.
The function works for all values of m. You input an x value and never get back more than one y value.meaning that this equation is only work for certain m value only.it is true?
tqvm
The function works for all values of m. You input an x value and never get back more than one y value.
The function does not have an inverse for every value for m.
Yep.Meaning that, there is no way that I can find the general inverse equation for that equation
Yep.