Stuck on some arithmetic

[spellbounded]

I use calcChat to check my homework and they tend to skip some basic simplifying steps so I need some clarification on a certain part. It goes from:

= (x+4)^-1/2 (x/2 + (x+4))

= (3/2x + 4)(x + 4)0

My question is where does the 3/2 come from?? Also there are 3 X's in step 1 then one of them is lost in the transition to step 2. If you want to view this worked out on calcchat, it is the calculus 9e book chapter 3 section 2 exercise 7.

 

[Steven G]

I use calcChat to check my homework and they tend to skip some basic simplifying steps so I need some clarification on a certain part. It goes from:

= (x+4)^-1/2 (x/2 + (x+4))

= (3/2x + 4)(x + 4)0 <-- If you multiply by 0 then the answer is 0!

My question is where does the 3/2 come from?? Also there are 3 X's in step 1 then one of them is lost in the transition to step 2. If you want to view this worked out on calcchat, it is the calculus 9e book chapter 3 section 2 exercise 7.

View attachment 5036

Why do x's 'disappear'? You combine them! Isn't 2x+3x =5x? And the lhs has 2-x's and the rhs has 1-x!!!!
(x/2 +(x+4))=x/2 + x + 4 = x/2 + 2x/2 + 4= 3x/2 +4. 1 + 1/2 = 3/2!!!!

 

[spellbounded]

hahah thank you!