Geometric sequence is 3/2, -3/4, and 3/8 are the first three terms. what represents the nth term of the sequence?
I know a is the first term, 3/2.
ratio is just a term divided by the term proceeding it.
ar^(n-1) is how you find a specific term.
I get all the way up to here: a(n) = ar^(n-1) = (3/2)(-1/2)^(n-1)
the final answer the book says, and this website I got help from: http://www.algebra.com/algebra/home...Sequences-and-series.faq.question.391759.html
says the final answer is:
a(n) = 3*(-1)^(n-1)/2^(n)
My question is, what happens to the other 2 in the denominator, and where does that n exponent in the denominator come from?
I know a is the first term, 3/2.
ratio is just a term divided by the term proceeding it.
ar^(n-1) is how you find a specific term.
I get all the way up to here: a(n) = ar^(n-1) = (3/2)(-1/2)^(n-1)
the final answer the book says, and this website I got help from: http://www.algebra.com/algebra/home...Sequences-and-series.faq.question.391759.html
says the final answer is:
a(n) = 3*(-1)^(n-1)/2^(n)
My question is, what happens to the other 2 in the denominator, and where does that n exponent in the denominator come from?