We can show the inverse to A2 exists if we can find a matrix to multiply it by to get the identity matrix.If A is an invertible nxn matrix, Prove A2 is also invertible.
I have tried by just using algebra definitions using the identity matrix, but can't quite seem to follow the right path.
We can show the inverse to A2 exists if we can find a matrix to multiply it by to get the identity matrix.
Let
A2 = B
Since we know A-1 exists, what would happen if we multiplied through by that? And then that again?