QwertyKnight
New member
- Joined
- May 3, 2015
- Messages
- 7
Hi guys,
I solved tan(2x)=cot(x), and i only got 2 solutions(+-(pi/6)+n*pi), but there's a third solution(pi/2 + k*pi). I already checked lot of websites, but on those websites there were only 2 solutions. How would i calculate that third solution? I would appreciate the help!
I solved tan(2x)=cot(x), and i only got 2 solutions(+-(pi/6)+n*pi), but there's a third solution(pi/2 + k*pi). I already checked lot of websites, but on those websites there were only 2 solutions. How would i calculate that third solution? I would appreciate the help!