separable equation

matt757

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Mar 24, 2015
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38
y'=1/1/sinx i have no idea were to start because the 1/1/sinx is throwing me off big time
 
y'=1/1/sinx i have no idea were to start because the 1/1/sinx is throwing me off big time

If your problem looks like this:

\(\displaystyle \displaystyle{y' \ = \ \frac{1}{\frac{1}{sin(x)}}}\)

then

\(\displaystyle \displaystyle{ \frac{1}{\frac{1}{sin(x)}} = sin(x)}\)

and continue....
 
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