Using Continuity to Calculate Limit

floatawayghost

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Jun 24, 2015
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So the instructions say:

For each limit use continuity to calculate the limit or explain why the Continuity of Simple Functions Theorem does not apply.

The limit is :

lim √x as x-->-5

I don't think you can plug in -5 to the function so I'm not sure what to do after that. I'm really confused about what to do and I just really need help.
 
For each limit use continuity to calculate the limit or explain why the Continuity of Simple Functions Theorem does not apply.

lim √x as x-->-5

I don't think you can plug in -5 to the function so I'm not sure what to do after that.


You are correct; negative numbers are not in the domain of the square-root function. The function's graph starts at the origin.

The instructions ask you to calculate the limit OR to explain why continuity cannot be used. You don't need to do both. :grin:

Ask yourself, "Is the function continuous at x = -5 ?"
 
Last edited:
"Existence" of a function is a "requirement" for continuity (which is a requirement for differentiability).
 
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