rectangle area is 2x^2 - 11x - 63, length is 2x + 7; find perimeter

[Ibbutibbu]

Please, I don't want an answer, Just help on how to complete this Quadratic Problem:

The area of a rectangle is \(\displaystyle \, 2x^2\, -\, 11x\, -\, 63\,\) square units, and the length is \(\displaystyle \, 2x\, +\, 7\,\) units. What is the perimeter, in units, of the rectangle?

 

[Deleted member 4993]

Please, I don't want an answer, Just help on how to complete this Quadratic Problem:

The area of a rectangle is \(\displaystyle \, 2x^2\, -\, 11x\, -\, 63\,\) square units, and the length is \(\displaystyle \, 2x\, +\, 7\,\) units. What is the perimeter, in units, of the rectangle?

If the area of a rectangle = A, and the length is = L

then width (W) = A/L

Now continue....