PipkinShamrock
New member
- Joined
- Nov 16, 2015
- Messages
- 2
The question is prove that |z+w|2-|z-wbar|2=4Re{z}Re{w}
(wbar means w with the bar over it, sorry I didn't know how to write it...)
I tried multiplying the left side out, and got |z2+2zw+w2|-|z2-2z(wbar)-(wbar)2|, but am confused about how to simplify sums of mods.
On the right side, I converted it to 2(z+zbar)(w+wbar), but that didn't get me anywhere either.
Can anyone guide me on where to go with this?
Thank you!
(wbar means w with the bar over it, sorry I didn't know how to write it...)
I tried multiplying the left side out, and got |z2+2zw+w2|-|z2-2z(wbar)-(wbar)2|, but am confused about how to simplify sums of mods.
On the right side, I converted it to 2(z+zbar)(w+wbar), but that didn't get me anywhere either.
Can anyone guide me on where to go with this?
Thank you!