Find two linearly independent power series solutions

pinky

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Hi,

My previous post didn't work so I've attached two files for the problem.
I don't really know how to get C2 and the recurrence. I don't fully understand it and have been following examples that I found in my book.
As for the last question, the book says to use c0=0 and C1=1. I answered the "answer is not shown" and both are 0, which are both incorrect.

If someone could help me with this problem that would be great.

Thank you in advance.
 

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Last edited:

Hi,
My question is:

Find two linearly independent power series solutions of the given differential equation about the ordinary point
x = 0.
2y'' + x2y' + xy = 0


Use: y(x) =
cnxn
sum.gif
n = 0

, and use the lower case letter c, for your subscripts in using c.

2y'' + x2y' + xy = 0

...
You work didn't come through. It looks like it is at least partially correct but you will have to find a different way to show us your work. I got c0 and c1 are arbitrary and c2=0 and a solution for the remainder of the coefficients of the form
\(\displaystyle c_{3(n+1)+j}\, =\, \alpha_{3n+j}\, c_{3n+j}\); j =0, 1, 2; n=0, 1, 2,...
where the \(\displaystyle \alpha_{3n+j}\) is determined by the differential equation. However, I haven't checked that answer.

Note that this says
(1) cj, j=3, 6, 9, ... depends only on c0
(2) cj, j=4, 7, 10, ... depends only on c1
(3) cj, j=5, 8, 11, ... depends only on c2 (and thus are 0)
 
You work didn't come through. It looks like it is at least partially correct but you will have to find a different way to show us your work. I got c0 and c1 are arbitrary and c2=0 and a solution for the remainder of the coefficients of the form
\(\displaystyle c_{3(n+1)+j}\, =\, \alpha_{3n+j}\, c_{3n+j}\); j =0, 1, 2; n=0, 1, 2,...
where the \(\displaystyle \alpha_{3n+j}\) is determined by the differential equation. However, I haven't checked that answer.

Note that this says
(1) cj, j=3, 6, 9, ... depends only on c0
(2) cj, j=4, 7, 10, ... depends only on c1
(3) cj, j=5, 8, 11, ... depends only on c2 (and thus are 0)

Hi, thanks for your response and I have fixed the post.
 
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