How can I find the direction vector of l'?

kvrck

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Joined
Jan 10, 2016
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Hi everyone. My question is:

Given l= {(x,y,z) = (x-1)/2 = (y+2)/-1 = z/3 }

find a line l' through (1,2,3) such that l and l' are skew.


I know that P(-1,+2,0) and u=(2,-1,3)

However, I do not know that direction vector (u) of l'.

If l and l' are skew, then l ∩ l' = ø and they are not parallel. So what? How can I find the direction vector of l'?


 
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