Hello!
I don't know why but this task is presenting a big problem for me, I am trying to solve it for more than an hour, but without success...
3. Suppose a random variable X follows a normal distribution with a mean \(\displaystyle \, \mu\, =\, 3\, \) and an unknown variance \(\displaystyle \, \sigma^2 .\,\) Moreover, it is given that, for 4% of the population, X > 5.11. What is the variance of X (rounded to two decimal places)?
A. 1.21. . .B. 1.45. . .C. 4.09. . .D. 16.72
I am trying to solve it using Chebyshev's theorem, but may be this is wrong Can anyone offer some help?
Thank you!
I don't know why but this task is presenting a big problem for me, I am trying to solve it for more than an hour, but without success...
3. Suppose a random variable X follows a normal distribution with a mean \(\displaystyle \, \mu\, =\, 3\, \) and an unknown variance \(\displaystyle \, \sigma^2 .\,\) Moreover, it is given that, for 4% of the population, X > 5.11. What is the variance of X (rounded to two decimal places)?
A. 1.21. . .B. 1.45. . .C. 4.09. . .D. 16.72
I am trying to solve it using Chebyshev's theorem, but may be this is wrong Can anyone offer some help?
Thank you!
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