Results 1 to 5 of 5

Thread: Help appreciated! :D solving ( 3y / 7 ) + ( y / 14) < -1

  1. #1

    Question Help appreciated! :D solving ( 3y / 7 ) + ( y / 14) < -1

    I don't remember how to do this....


    (3y/7)+(y/ 14)<−1

    So, here is my work...

    (3y/7)+(y/ 14) < -1

    [2] (3y/7)+(y/ 14) < -1

    (6y/14)+(y/ 14) < -1

    7y / 14 < -1

    1/2y < -1



    y < -2


    Is this correct?

    Thanks!!! :) :D

  2. #2
    Elite Member
    Join Date
    Jun 2007
    Posts
    17,481
    Quote Originally Posted by Againstheworld View Post
    I don't remember how to do this....


    (3y/7)+(y/ 14)<−1

    So, here is my work...

    (3y/7)+(y/ 14) < -1

    [2 /2 ] (3y/7)+(y/ 14) < -1

    (6y/14)+(y/ 14) < -1

    7y / 14 < -1

    1/2y < -1



    y < -2


    Is this correct?

    Thanks!!!
    Yes....
    “... mathematics is only the art of saying the same thing in different words” - B. Russell

  3. #3
    Elite Member
    Join Date
    Jul 2014
    Posts
    3,386
    Quote Originally Posted by Againstheworld View Post
    I don't remember how to do this....


    (3y/7)+(y/ 14)<−1

    So, here is my work...

    (3y/7)+(y/ 14) < -1

    [2] (3y/7)+(y/ 14) < -1

    (6y/14)+(y/ 14) < -1

    7y / 14 < -1

    1/2y < -1



    y < -2


    Is this correct?

    Thanks!!!
    Issac Asimov once said something to the affect of "Although it is sometimes a convenience, I don't have to remember things, A genius can work them out and, since I can work them out, I'm a genius."

    -Ishuda

  4. #4

    Red face

    Quote Originally Posted by Ishuda View Post
    Issac Asimov once said something to the affect of "Although it is sometimes a convenience, I don't have to remember things, A genius can work them out and, since I can work them out, I'm a genius."
    Thanks!!! That is an awesome quote ^.^

  5. #5
    Senior Member
    Join Date
    Aug 2010
    Posts
    2,364
    Quote Originally Posted by Againstheworld View Post
    I don't remember how to do this....


    (3y/7)+(y/ 14)<−1

    So, here is my work...

    (3y/7)+(y/ 14) < -1

    [2] (3y/7)+(y/ 14) < -1 <------ this line

    (6y/14)+(y/ 14) < -1

    7y / 14 < -1

    1/2y < -1



    y < -2


    Is this correct?

    Thanks!!!
    No, it's not correct.

    The line above makes it incorrect.

    [2](3y/7) = 6y/7, not 6y/14.




    - - - - - -- - - -- - - - - - -- - - - - - - -

    Look at:


    (3y/7) + (y/14) < -1

    [2/2](3y/7) + (y/14) < -1

    (6y/14) + (y/14) < -1

    7y/14 < -1

    (1/2)y < -1

    y < -2

Tags for this Thread

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •