Trigonometric Identities Problem

[softkitty]

"Show that the equation 4cosec^2x - cot^2x = k, where k =/= 4, can be written in the form sec^2x = (k-1)/(k-4)"

So far I got to 3 / (1- cos^2x) = k -1, I can't seem to see where the other k comes from - is it to do with the fact hat k =/= 4 somehow?

Any help much appreciated.


This is from a very recent AQA GCE maths paper, the mark scheme of which I don't have access to!

 

[starTman08]

"Show that the equation 4cosec^2x - cot^2x = k, where k =/= 4, can be written in the form sec^2x = (k-1)/(k-4)"

So far I got to 3 / (1- cos^2x) = k -1, I can't seem to see where the other k comes from - is it to do with the fact hat k =/= 4 somehow?

Any help much appreciated.


This is from a very recent AQA GCE maths paper, the mark scheme of which I don't have access to!

1. Don't need focus on k≠4, it stands there just make sure we have the right equation.

2. put all of k into (k-1)/(k-4)

3. Maybe you stuck here.