Missing side of triangular prism w/ vol 60ft^3, base 4ft by 6ft, side's base is 4ft

g_bway

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The volume of a tent (triangular prism) is 60ft^3 the floor is 4ft by 6ft, the front and back doors are isosceles triangels with a base of 4ft. What is the missing length?

I am not sure what formula to use or how to use it, the teacher said there might be more than one solution, if you could just explain the work I have to to solve this it would be greatly appreciated. Thanks!
 
The volume of a tent (triangular prism) is 60ft^3 the floor is 4ft by 6ft, the front and back doors are isosceles triangels with a base of 4ft. What is the missing length?

I am not sure what formula to use or how to use it, the teacher said there might be more than one solution, if you could just explain the work I have to to solve this it would be greatly appreciated. Thanks!

This is triangular prism with height = h = 6

Let the side of the isosceles triangle be 'a' (the missing length) .... Edit

Then the triangular base is made of 'a' 'a' and 4.

Using Herons formula

S = a + 2

Area of triangular base = √[(a+2) * 2 * 2 * (a-2)] ...... edit

Volume of prism = h * (area of base)

continue.....
 
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