Volumes of a solid of revolution: between y= 32x-8x^2 & y=0, about y-axis

[rmcginn]

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y= 32x-8x^2
y=0
about the y=axis.

 

[Deleted member 4993]

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y= 32x-8x^2
y=0
about the y=axis.

What are your thoughts?

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[Prove It]

Have you at least drawn a sketch of your function? Marked in the region to be rotated? Determined its endpoints? Figured out what it would look like to break up into rectangles and then rotate each rectangle?