Hydrostatic Force: A cylindrical tank w/ diam of 6m is placed so axis is horizontal.

[conniechung]

A cylindrical tank with a diameter of 6m is placed so that the axis of the cylinder is horizontal. Find the fluid force on a circular end of the tank if the tank is half full. The density of water is 1000kg/m^3 and the acceleration of gravity is 9.8m/s^2.

1. Set up the integral to determine the force.
I tried and got the integral of ((1000)(9pi/2)(9.8)(3-y))dy from 0 to 3

I integrated it, but I didn't get the answer that my teacher gave us, which was 176,400 newtons
Can someone help explain to me how to set up the integral!

 

[Deleted member 4993]

A cylindrical tank with a diameter of 6m is placed so that the axis of the cylinder is horizontal. Find the fluid force on a circular end of the tank if the tank is half full. The density of water is 1000kg/m^3 and the acceleration of gravity is 9.8m/s^2.

1. Set up the integral to determine the force.
I tried and got the integral of ((1000)(9pi/2)(9.8)(3-y))dy from 0 to 3

I integrated it, but I didn't get the answer that my teacher gave us, which was 176,400 newtons
Can someone help explain to me how to set up the integral!

As I see the problem, this problem needs to be double integral ( area integral)

Assume the origin to be center

x will go from -3 to +3

y will go from 0 to √(9 -x²)

Now continue...