Jane left place A at 8.00 am towards place B at an average speed of 90km per hour.

[The bawse]

Jane left place A at 8.00 am towards place B at an average speed of 90km per hour. Kate left place B at 8.21 am towards place A along the same road at an average speed of 97km per hour.

Please help!!!!

 

[stapel]

Please help!!!!

We'll be glad to! But, in order to get started, we'll need to know what the actual question was, and we'll need to see what you've done so far (so we can see where you're needing the help). For further information, please re-read the "Read Before Posting" announcement.

Jane left place A at 8.00 am towards place B at an average speed of 90km per hour. Kate left place B at 8.21 am towards place A along the same road at an average speed of 97km per hour.

This is the beginning of an exercise. Back in algebra, you did exercises that started similarly. The exercises usually went on to ask things like "Determine the exact time at which Jane and Kate met along the rode between Place A and Place B", and you'd have used basic algebra to compute the answer.

However, now you're in calculus, so presumably the rest of the exercise is much more involved. Please reply with that info, along with a complete listing of your thoughts and efforts so far. Thank you!

 

[SAMUELK]

Well, at 8.21 Jane had travelled 21/60 * 90 = 31.5km;
at this point, Kate takes off.
They are travelling at combined speed of 90+97=187km per hour.
How long will it take before they meet?
Good question! BUT what's the distance between A and B?

If d = distance, then they travel for:
(d - 31.5) / 187 hours, following 8.21 am

If you can't follow that, see your teacher...

This sounds like an elementary algebra problem.

BUT, maybe it says "Assume Jane and Kate travel at varying speeds (as in real life), stop for lunch, rest stops, etc. Prove there exists a point between A and B such that Jane and Kate pass it at exactly the same time."

THEN it's a calculus problem.

 

[Deleted member 4993]

Hmmm...I can't follow that, Sam.

If distance between A an B is greater than 31.5km,
then they will meet.
If equal or lesser than 31.5km, then they will not meet.

Isn't that obvious?

Jane left place A at 8.00 am towards place B at an average speed of 90km per hour. Kate left place B at 8.21 am towards place A along the same road at an average speed of 97km per hour.

If equal or lesser than 31.5km, .... ← That cannot be. In that case, Jane has reached B (and met Katie before she started) and going past...