2 people flip a coin; each flips it 50 times, then counts number of heads; prob. same

[starjo]

can anyone help me with this ?

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0.000

- Two people flip a coin

- Each person flips it 50 times

- Each person then counts the number of heads.

- What is the probability that they both get the same number of heads?​

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please i need help <3

Thanks

 

[stapel]

can anyone help me with this ?

Certainly! But first we'll need to see where you're needing the help!

0.000

- Two people flip a coin

- Each person flips it 50 times

- Each person then counts the number of heads.

- What is the probability that they both get the same number of heads?​

​

You posted this to "Arithmetic" rather than to "Probability/Statistics", so presumably you haven't even taken pre-algebra. So we'll need to try to help you use whatever pre-algebraic methods they taught you to use. However, until you tell us what those methods were, we'll be unable to move forward.

So please reply with a clear listing of the rules, formulas, etc, that they gave you in class to use, along with a complete statement of your thoughts and efforts so far. Thank you!

 

[pka]

- Two people flip a coin
Each person flips it 50 times
Each person then counts the number of heads.
What is the probability that they both get the same number of heads?

I echo, the advise that you absolutely must show your own efforts.
Having said that, this is a very difficult problem conceptually.
Look at this web-link. That utility can be very useful in working this question.
I expect you to figure out why that calculation gives the probability that one player will throw exactly fifteen heads.
Why is that also the probability that the player will throw exactly thirty-five heads?
Why does that symmetry mean that all we need do is twenty-six calculations?

Now here is the critical concept: What is the probability that both player will throw exactly fifteen heads? (think exponent)

What summation do we need to answer the question completely?