take away 30% of the 3 grams. How many grams do I have left?

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Let's say I have 3 grams.

And I am take away 30% of the 3 grams.

How many grams do I have left? Also how do I do the math?
 
Let's say I have 3 grams.

And I am take away 30% of the 3 grams.

How many grams do I have left? Also how do I do the math?

If you take away 30% then you'll have 70% left. Right?

So, you need to find 70% of 3 grams.

% means "per hundred", so you need to find \(\displaystyle \frac{70}{100}*3\).

Grab a calculator.
 
If you take away 30% then you'll have 70% left. Right?

So, you need to find 70% of 3 grams.

% means "per hundred", so you need to find \(\displaystyle \frac{70}{100}*3\).

Grab a calculator.

So 70% of 3 grams is 2.1 grams?

Thank you so munch!
 
Thanks for the reply!

I grabbed a calculator and..

70% of 3 grams is 2.1 grams? Am I correct?
 
I grabbed a calculator and..

70% of 3 grams is 2.1 grams?

Am I correct?

Are you doubting the calculator?

Try this way:

70/100 reduces to 7/10

7 times 3 is in the multiplication table

Dividing 21 by 10 shifts its decimal point one place to the left

Look ma, no hands! :D
 
If I tattoo that on my wrist then I will be a cheater for life..

I then take 2.1 and subtract that from 3 and I get 0.9.

So 30% of 3 grams is 0.9 grams.

I'm working on a project that calls for 3 grams of thick sauce in a 1-1/2" long/tall tube and 5/8" inner diameter.
And that tube needs to be filled two thirds full of 3 grams.
That tube is suppose to contain 30% cornstarch and 70% liquid BBQ sauce. ( The corn starch makes it thicker with a pleasant taste.

Now I need to figure this out for a tube that is 3" long/tall with a 2" inner diameter.
This tube also calls for 70% BBQ liquid sauce and 30% cornstarch.

How many grams would I need to fill it up two thirds full? How do I do the math?
 
If I tattoo that on my wrist then I will be a cheater for life..

I then take 2.1 and subtract that from 3 and I get 0.9.

So 30% of 3 grams is 0.9 grams.

I'm working on a project that calls for 3 grams of thick sauce in a 1-1/2" long/tall tube and 5/8" inner diameter.
And that tube needs to be filled two thirds full of 3 grams.
That tube is suppose to contain 30% cornstarch and 70% liquid BBQ sauce. ( The corn starch makes it thicker with a pleasant taste.

Now I need to figure this out for a tube that is 3" long/tall with a 2" inner diameter.
This tube also calls for 70% BBQ liquid sauce and 30% cornstarch.

How many grams would I need to fill it up two thirds full? How do I do the math?

Your problem statement is Khan-fusing!

Is it a homework? If it is - please post the original problem as it was presented to you.
 
It is not homework related.

I'm just trying to figure out how many grams I can fit in a 3" long tube with a 2" ID. (Inner diameter)
I only want the tube to be two thirds full of grams.

How do I do the math to figure it out?
 
Sorry. But how do I calculate pi * h * r^2 ?

How would I enter that in the calculator?

Is pi= π ?

h = height?

r = radius?

Square 2?

I could send you some. You can count on it.
 
Sorry. But how do I calculate pi * h * r^2 ?

How would I enter that in the calculator?

Is pi= π ?

h = height?

r = radius?

Square 2?

I could send you some. You can count on it.

Well, yes, the above inferences are correct about what the mathematical symbols mean. However, you're still short one piece of information to be able to solve your problem. Doing the calculations will result in the volume of the cylinder, which will be in liters, not grams. To determine how many grams of something will fit in a specific volume, you need to know the density of that something.
 
I'm working on a project that calls for 3 grams of thick sauce in a 1-1/2" long/tall tube and 5/8" inner diameter.
And that tube needs to be filled two thirds full of 3 grams.
That tube is suppose to contain 30% cornstarch and 70% liquid BBQ sauce. ( The corn starch makes it thicker with a pleasant taste.

Now I need to figure this out for a tube that is 3" long/tall with a 2" inner diameter.
This tube also calls for 70% BBQ liquid sauce and 30% cornstarch.

How many grams would I need to fill it up two thirds full? How do I do the math?

Volume of first cylinder = π/4 * d^2 * h = 0.460194 in^3

density of mixture = 3/(2/3 * 0.460194) = 9.77848 gms/in^3

Volume of second cylinder = π/4 * d^2 * h = 9.424778 in^3

Weight of mixture needed = 2/3 *9.424778 * 9.77848 gms = ?
 
61.44 grams to fill a 3" tall 2" radius tube two thirds full?

Answer is 61.44 grams?

And I just use that 4 stop process every time?
 
61.44 grams to fill a 3" tall 2" radius tube two thirds full?

Answer is 61.44 grams?

And I just use that 4 stop process every time?
NO!!

Now I need to figure this out for a tube that is 3" long/tall with a 2" inner diameter.
This tube also calls for 70% BBQ liquid sauce and 30% cornstarch.

It was 2" diameter (1" radius)!!
 
My apologies.

61.44 grams will fill a 3" tall tube 1" radius?

Is there easier steps to get the result?
 
It is unnecessary for you and me, but I assumed the OPer may need to use one. And I wasn't going to state the answer.
No! This is all about the the OPer. She/He needs NOT to use a calculator! These are idiot machines for the beginners. Actually you and I can use a calculator as we know how to do basic math.
 
You can give me the answer, because in real life, I'm a proffesional mathematican.

I'm known as Dr. Math.

But I only know about the complicated formulas. Most of them.

So you can give me the answer.
 
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