A room has dimensions Length = 12 feet, breadth = 8 feet, Height= 6 feet.

Justin1921

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A room has dimensions Length = 12 feet, breadth = 8 feet, Height= 6 feet. Find the cost of painting the room (four walls and ceiling) at cost of 5 cents per square foot. Assume area of doors and windows of the room is 60 square feet which is not to be painted.

Please help me solve this.
 
A room has dimensions Length = 12 feet, breadth = 8 feet, Height= 6 feet. Find the cost of painting the room (four walls and ceiling) at cost of 5 cents per square foot. Assume area of doors and windows of the room is 60 square feet which is not to be painted.

What are your thoughts?

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Sir i actually working for one of my test,
I am simply L x B x W i-e 12 x 8 x 6 = 576
then i am subtracting 60 (Area of doors and windows), 576 - 60 = 516
and then finally multiplying it with 5 cents.
The Answer i am getting is = 2580 cents
But the answer is 1380 cents !

Please solve this for me.
 
A room has dimensions Length = 12 feet, breadth = 8 feet, Height= 6 feet. Find the cost of painting the room (four walls and ceiling) at cost of 5 cents per square foot. Assume area of doors and windows of the room is 60 square feet which is not to be painted.

Please help me solve this.

There are 4 walls in the room. If the Room is L ft long, W ft wide and H ft high

Area of 4 walls = 2*H * L + 2 * H * W

Area of the ceiling = L * W

continue...
 
There are 4 walls in the room. If the Room is L ft long, W ft wide and H ft high

Area of 4 walls = 2*H * L + 2 * H * W

Area of the ceiling = L * W

continue...


Thanks alot Sir, really appreciate your reply.
Sorry to bother you again and again but i am still not able to sort out the problem.
 
Sir i actually working for one of my test,
I am simply L x B x W i-e 12 x 8 x 6 = 576
then i am subtracting 60 (Area of doors and windows), 576 - 60 = 516
and then finally multiplying it with 5 cents.
The Answer i am getting is = 2580 cents
But the answer is 1380 cents !

Please solve this for me.
L x B x W gives you the volume. You need the total surface area.
 
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