How does theta change with psi?
I've tried solving it this way:
Which led me to the equation: [tex]r+40e\sin\theta=(e+r)\sin(\psi-\theta)[/tex]
But I simply don't know how to proceed.
How does theta change with psi?
I've tried solving it this way:
Which led me to the equation: [tex]r+40e\sin\theta=(e+r)\sin(\psi-\theta)[/tex]
But I simply don't know how to proceed.
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