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Thread: How does THETA change with PSI? (irregular polygon)

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    How does THETA change with PSI? (irregular polygon)



    How does theta change with psi?

    I've tried solving it this way:



    Which led me to the equation: [tex]r+40e\sin\theta=(e+r)\sin(\psi-\theta)[/tex]

    But I simply don't know how to proceed.
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