I have this equation and I know what the final answer should be but I am stuck on how to get to it using derivatives. Thanks in advance
Solving for t
-Xe^{-xt }+ Ye^{-yt }Final answer should be
t= ln(y/x)(1/(y-x))
I have this equation and I know what the final answer should be but I am stuck on how to get to it using derivatives. Thanks in advance
Solving for t
-Xe^{-xt }+ Ye^{-yt }Final answer should be
t= ln(y/x)(1/(y-x))
Assuming x and X are meant to be the same thing (and that's a BIG assumption) and the same for the Y and y:
[tex]-xe^{-xt} + ye^{-yt} =0 [/tex]
[tex] y*e^{-yt} = x* e^{-xt} [/tex]
[tex]\frac {y}{x} = \frac {e^{-xt}}{e^{-yt}} [/tex]
[tex]\frac{y}{x} = e^{yt-xt}[/tex]
Now take natural log of both sides and see if you can make t the subject.
Heavens to Murgatroyd!!
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