Dear friends,

I am unable to find out the unknown angles for the following triangle which I attached with this post.

Angle BADandangle BCDare the unknown angles need to be calculated. Given that linesAB=BC=CDandangle CDE = 108 degrees

From my calculations:angle ADC= 180 - 108 =72 degrees(angles on a straight line)

angle BAD + angle BCD =108 degrees(exterior angle of a triangle = sum of interior opposite angles)

I could not proceed any further beyond this. I thoughtline DB(median) is bisectingangle ADCsinceline DBis bisectingline AC(AB=BC) but this only happens in case of isosceles and equilateral triangles.

I am very much stuck here and seek your kind suggestions here. I am also suspecting something could be wrong in the diagram of the triangle or may be the unknown angles. Let me know where I am wrong. Thanks in advance.

## Bookmarks