7 Consecutive numbers: 1/4 of smallest is 5 less than 1/3 of largest

Joanster1963

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Hi, my niece has some homework which ive been helping her with and i can work out the answer easy enough but by using trial and error really. I was wondering whether there was a way or formula which can be used to solve the problem properly? So she knows for future questions.
Q: in a sequence of 7 consecutive numbers a quarter of the smallest number is five less than a third of the largest number. What is the value of the smallest number?
 
Hi, my niece has some homework which ive been helping her with and i can work out the answer easy enough but by using trial and error really. I was wondering whether there was a way or formula which can be used to solve the problem properly? So she knows for future questions.
Q: in a sequence of 7 consecutive numbers a quarter of the smallest number is five less than a third of the largest number. What is the value of the smallest number?
Let the consecutive numbers be: S, S+1, S+2, S+3, S+4, S+5, S+6
Then,
S/4 = (S+6)/3 - 5

Solve for 'S'.
 
Hi, my niece has some homework which ive been helping her with and i can work out the answer easy enough but by using trial and error really. I was wondering whether there was a way or formula which can be used to solve the problem properly? So she knows for future questions.
Q: in a sequence of 7 consecutive numbers a quarter of the smallest number is five less than a third of the largest number. What is the value of the smallest number?
You've posted this to "Arithmetic", which suggests that the student is somewhere in K-6 studies, not having seen any algebra yet. This limits possible solution methods severely. Are you sure that she hasn't done any algebra at all? Thank you! ;)
 
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