I have 5 procedures listed below:
1. (x+y+z)/x1=252.81
2. (x+1.5y+z)/x1=292.13
3. (2x+1.5y+z)/x1=449.44
4. (2x+2y+2z)/x1=505.62
5. (3x+2y+2z)/x1=662.92
x, y, z & x1 are variables but used identical in each procedure. Considering the related procedures what is the possibility to find at least one of the value assigned to x or y? If not possible from the given figures the proximate value of z can be estimated (15) but x, y, & x1 are always unpredictable.
The calculated values in procedures above are:
1. (140+70+15)/0.89=252.81
2. (140+105+15)/0.89=292.13
3. (280+105+15)/0.89=449.44
4. (280+140+30)/0.89=505.62
5. (420+140+30)/0.89=662.92
Thanks in advance.
1. (x+y+z)/x1=252.81
2. (x+1.5y+z)/x1=292.13
3. (2x+1.5y+z)/x1=449.44
4. (2x+2y+2z)/x1=505.62
5. (3x+2y+2z)/x1=662.92
x, y, z & x1 are variables but used identical in each procedure. Considering the related procedures what is the possibility to find at least one of the value assigned to x or y? If not possible from the given figures the proximate value of z can be estimated (15) but x, y, & x1 are always unpredictable.
The calculated values in procedures above are:
1. (140+70+15)/0.89=252.81
2. (140+105+15)/0.89=292.13
3. (280+105+15)/0.89=449.44
4. (280+140+30)/0.89=505.62
5. (420+140+30)/0.89=662.92
Thanks in advance.