This is my first post, so not quite sure if syntax is correct or if this should be in beginning algebra or intermediate/advanced algebra. I'm taking the course College Algebra.

Book says answer is x=(1-a)/(a^2-a-1)

I've tried 3 different ways, but think I may be distributing prematurely when there would be an easier way:

1) (a^2)x+(a-1)=(a+1)x

(a^2)x+(a-1)=ax+x

-x+(a^2)+(a-1)=ax

(a^2)-x+a-1=(ax)/x

-x=(-a^2)-a+1+((ax)/x)

x=(a^2)+a-1-((ax)/x)

I don't know if this is correct or how to get my answer into book answer form from here.

2) (a^2)x+(a-1)=(a+1)x

(a^2)x=-a+1+(a+1)x

x=(-a+1+(a+1)x)/a^2

x=(-a+1+ax+x)/a^2

x=(1-a+ax+x)/a^2

Again, don't know if this is correct or how to get into book form.

3) (a^2)x+(a-1)=(a+1)x if I divide both sides by a^2, do I do it like this:

x+(a-1)=((a+1)x)/a^2 or like this:

x+((a-1)/a^2)=((a+1)x)/a^2 ???

Please help, it's early in the morning and I'm all cracked out on coffee!!!! : P

Thanks so much,

Tammie : )