**Re: Beginning Algebra**

A rectangle is three times as long as it is wide. If its lenght and width are both decreased by 2 cm, its area is decreased by 36 cm2. Find it orginal dimensions.

(3x-40(x-4) + 3x2(x) = x + 36

-12x -4x + 16 = x+ 36

-16x = X + 20

Please explain and show work.

Thanks,

X = width

3x = length

Then, x(3x) - (x - 2)(3x - 2) = 36.

3x^2 - 3x^2 + 8x - 4 = 36

8x = 40

I bet you can take it from here.