- Thread starter mnmathkid
- Start date

Oh! that looks right.... so I think you're saying that the ||'s arent needed and the problem is just like x^2 + |y| = 1 or, if I rewrite it, then a parabola like:tkhunny said:Have you noticed that x^2 >= 0, so that |x^2| = x^2?

y = 1 - x^2 AND y = x^2 - 1

and I know how to figure out the domains with my TI so whoa, whoa!

Thanks for your tip.

thanks for that interesting twist! very cool.Gene said:Or

|y| = 1-x² is the same as

y=|1-x²|

They are both based on y=1-x² and it doesn't matter which side you do it to.