Say you want find LCD of 3 and 15Katie1 said:I am having problems doing this, I can do the simple ones such as[3/4b^2+5/3b^3
But when I get to 2x/(x^2+5x+6)-4/(x-2) I get lost.
LCD for (x^2+5x+6)=(x-2)(x-3)
LCD for (x-2)= (x-2)
So the LCD= (x-2)(x-3)-----------Yes?