Hi I am having a heck of a time trying to find this answer. 3(n-2)3 I thought it would be3n-6
H heather97423 New member Joined Feb 25, 2014 Messages 1 Feb 25, 2014 #1 Hi I am having a heck of a time trying to find this answer. 3(n-2)3 I thought it would be3n-6 Last edited by a moderator: Feb 25, 2014
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 Feb 25, 2014 #2 heather97423 said: Hi I am having a heck of a time trying to find this answer. 3(n-2)3 Click to expand... Is the expression as follows? . . . . .\(\displaystyle 3\left(n^{-2}\right)^3\) heather97423 said: I thought it would be 3n-6 Click to expand... What do you think the "correct" answer is? Thank you!
heather97423 said: Hi I am having a heck of a time trying to find this answer. 3(n-2)3 Click to expand... Is the expression as follows? . . . . .\(\displaystyle 3\left(n^{-2}\right)^3\) heather97423 said: I thought it would be 3n-6 Click to expand... What do you think the "correct" answer is? Thank you!
W wjm11 Senior Member Joined Nov 13, 2004 Messages 1,417 Feb 25, 2014 #3 heather97423 said: Hi I am having a heck of a time trying to find this answer. 3(n-2)3 I thought it would be3n-6 Click to expand... Are there any stipulations about what form to leave your answer in? Such as: no negative exponents??? Why do you think your answer is wrong?
heather97423 said: Hi I am having a heck of a time trying to find this answer. 3(n-2)3 I thought it would be3n-6 Click to expand... Are there any stipulations about what form to leave your answer in? Such as: no negative exponents??? Why do you think your answer is wrong?