# algebra help: mixing solutions to get 60 L of 30%-acid soln

#### martanks

##### New member
Solution A is 25% acid and Solution B is 40% acid. How much of each is needed to make 60 liters of a solution that is 30% acid?

#### skeeter

##### Senior Member
Re: algebra help

let x = amount of solution A in liters
60-x = amount of solution B in liters

x(.25) + (60-x)(.40) = 60(.30)

solve for x, then you can also determine 60-x

#### martanks

##### New member
Re: algebra help

but then how do i solve for x???

#### stapel

##### Super Moderator
Staff member
martanks said:
but then how do i solve for x???
Hmm... that's awkward. Your class was supposed to have covered solving linear equations, at length and in depth, well before moving on to setting up and solving linear equations from word problems! :shock:

To learn how to solve linear equations, please consider studying from some of the many great lessons available online:

. . . . .Google results for "solving linear equations"

Once you have studied some lessons (at least two!) and have learned the basic terms and techniques, please attempt to finish this exercise (starting from the set-up already provided by the tutor). If you get stuck, please reply with a clear listing of your work and reasoning. Thank you!

Eliz.