- Thread starter haleofwi
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No. You need to start by adding 14 to both sides:haleofwi said:I'm not sure how to work this one. Can anyone help?

(2x)/3-14=4

This is what I did: 2x/3-14=4

2x/-11=4

2x/-11+11=4+11

2x=15

2x/2=15/2

x=15/2 ?

is this right???

(2x) / 3 = 18

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Does this mean the following?haleofwi said:(2x)/3 - 14 = 4

. . . . .\(\displaystyle \L \frac{2x}{3}\, -\,14\, =\, 4\)

Or this?

. . . . .\(\displaystyle \L \frac{2x}{3\, -\, 14}\, =\, 4\)

If the former, then you cannot combine the 3 and the 14 into the denominator, since the 14 isn't in there anyway.

Since the "11" is in the denominator, how could adding an 11 possibly "cancel" this off?haleofwi said:2x/-11 + 11 = 4 + 11

. . . . .\(\displaystyle \L \frac{2x}{-11}\, + \, 11\)

And even if it did somehow cancel the denominator, you would end up with a zero in the denominator, which isn't allowed.

Have you not studied fractions previously...?

Eliz.