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algerba

rrolo31

New member
Joined
Dec 26, 2009
Messages
1
cannot solve please help

x2/x-3=x2/1x3=(x2)(x3)=x3
 

Aladdin

Full Member
Joined
Mar 27, 2009
Messages
553
rrolo31 said:
cannot solve please help

x2/x-3=x2/1x3=(x2)(x3)=x3
What's this !

Please type clearer .
 

soroban

Elite Member
Joined
Jan 28, 2005
Messages
5,588
Helolo, rrolo31!

cannot solve please help

x2/x-3=x2/1x3=(x2)(x3)=x3

Even with my wildest guessing, it doesn't make any sense . . .

\(\displaystyle \frac{x^2}{x}-3 \;=\;\frac{x^2}{1x^3} \;=\;(x^2)(x^3) \;=\;x^3\)

\(\displaystyle \frac{x^2}{x-3} \;=\;\frac{x^2}{1\times3} \;=\;(x^2)(x^3) \;=\;x^3\)


What is the equation ?

 

chrisr

Full Member
Joined
Nov 29, 2009
Messages
355
Looks like the student tried to label subscripts

\(\displaystyle \frac{x_2}{x-3}=\frac{x_2}{x_3}=(x_2)(x_3)=x_3\)

giving \(\displaystyle x_2=1\)

\(\displaystyle (x_3)^2=1,\quad x_3=1\quad or\quad -1\)
\(\displaystyle x=2\quad or\quad 4\)
 
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