Find the derivative of f(x)=x^2ln(x). f'(x)=2x(ln(x))+x^2*1 f'(x)=2x(1/x) + x^2 Thanks!
L lbaird New member Joined May 15, 2006 Messages 3 May 15, 2006 #1 Find the derivative of f(x)=x^2ln(x). f'(x)=2x(ln(x))+x^2*1 f'(x)=2x(1/x) + x^2 Thanks!
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 May 15, 2006 #2 Re: Could someone please tell me if I'm on the right track lbaird said: Find the derivative of f(x)=x^2ln(x). f'(x)=2x(ln(x))+x^2*1 Click to expand... The derivative of ln(x) is not 1. lbaird said: f'(x)=2x(1/x) + x^2 Click to expand... It looks here like you're saying that ln(x) equals 1/x...? This isn't true. Eliz.
Re: Could someone please tell me if I'm on the right track lbaird said: Find the derivative of f(x)=x^2ln(x). f'(x)=2x(ln(x))+x^2*1 Click to expand... The derivative of ln(x) is not 1. lbaird said: f'(x)=2x(1/x) + x^2 Click to expand... It looks here like you're saying that ln(x) equals 1/x...? This isn't true. Eliz.
skeeter Elite Member Joined Dec 15, 2005 Messages 3,215 May 15, 2006 #3 f(x) = x^2*lnx product rule, correct? f'(x) = x^2*(1/x) + lnx*2x f'(x) = x + 2x*lnx = x(1 + 2lnx)
