S sandyk109 New member Joined May 7, 2007 Messages 15 Jun 8, 2007 #1 A hockey team played 12 games. They won two more than they lost. They lost one more than they tied. How many games did they win, lose and tie? my answer: w +(w + 2) + (w + 1) = 12 book answer: x +(x + 1) + [ (x + 1) + 2] = 12 Please explain and show steps. Thanks

A hockey team played 12 games. They won two more than they lost. They lost one more than they tied. How many games did they win, lose and tie? my answer: w +(w + 2) + (w + 1) = 12 book answer: x +(x + 1) + [ (x + 1) + 2] = 12 Please explain and show steps. Thanks

J jwpaine Full Member Joined Mar 10, 2007 Messages 723 Jun 8, 2007 #2 {L = W + 2 {L = T + 1 {L + W + T = 12 Solve the system of equations for L, W and T (loss, win, tie). John.

{L = W + 2 {L = T + 1 {L + W + T = 12 Solve the system of equations for L, W and T (loss, win, tie). John.

D Denis Senior Member Joined Feb 17, 2004 Messages 1,652 Jun 9, 2007 #3 sandyk109 said: book answer: x +(x + 1) + [ (x + 1) + 2] = 12 Click to expand... That leads to 3x = 8; so book wrong! Something wrong with the problem: you sure it's not 13 games?

sandyk109 said: book answer: x +(x + 1) + [ (x + 1) + 2] = 12 Click to expand... That leads to 3x = 8; so book wrong! Something wrong with the problem: you sure it's not 13 games?