Beginning Albebra

sandyk109

New member
Joined
May 7, 2007
Messages
15
A hockey team played 12 games. They won two more than they lost. They lost one more than they tied. How many games did they win, lose and tie?

my answer:

w +(w + 2) + (w + 1) = 12

book answer:

x +(x + 1) + [ (x + 1) + 2] = 12

Please explain and show steps. Thanks
 

jwpaine

Full Member
Joined
Mar 10, 2007
Messages
723
{L = W + 2
{L = T + 1
{L + W + T = 12

Solve the system of equations for L, W and T (loss, win, tie).

John.
 

Denis

Senior Member
Joined
Feb 17, 2004
Messages
1,641
sandyk109 said:
book answer:
x +(x + 1) + [ (x + 1) + 2] = 12
That leads to 3x = 8; so book wrong!
Something wrong with the problem: you sure it's not 13 games?
 
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