C cmtoland New member Joined Sep 8, 2015 Messages 2 Sep 8, 2015 #1 How would you solve this: (5n+1)/8 = (3n-5)/4 Last edited by a moderator: Sep 8, 2015

stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 15,943 Sep 8, 2015 #2 cmtoland said: How would you solve this: (5n+1)/8 = (3n-5)/4 Click to expand... How would you solve this? . . . . .a. 5n + 1 = 3n - 5 How would you solve this? . . . . .b. 2(5n + 1) = 3n - 5 What do you get if you multiply your posted equation, on both sides, by the Lowest Common Denominator of the two fractions? ;-)

cmtoland said: How would you solve this: (5n+1)/8 = (3n-5)/4 Click to expand... How would you solve this? . . . . .a. 5n + 1 = 3n - 5 How would you solve this? . . . . .b. 2(5n + 1) = 3n - 5 What do you get if you multiply your posted equation, on both sides, by the Lowest Common Denominator of the two fractions? ;-)

8 8char New member Joined Sep 9, 2015 Messages 3 Sep 9, 2015 #3 First we get rid of the denominators by multiplying both sides by 8. Now we get (5n+1)=2(3n-5). We then expand everything and get 5n+1=6n-10, this turns into... what? Last edited by a moderator: Sep 9, 2015

First we get rid of the denominators by multiplying both sides by 8. Now we get (5n+1)=2(3n-5). We then expand everything and get 5n+1=6n-10, this turns into... what?