Beginning Algebra 1: How would you solve this: (5n+1)/8 = (3n-5)/4

cmtoland

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How would you solve this: (5n+1)/8 = (3n-5)/4

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stapel

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How would you solve this: (5n+1)/8 = (3n-5)/4
How would you solve this?

. . . . .a. 5n + 1 = 3n - 5

How would you solve this?

. . . . .b. 2(5n + 1) = 3n - 5

What do you get if you multiply your posted equation, on both sides, by the Lowest Common Denominator of the two fractions? ;-)

8char

New member
First we get rid of the denominators by multiplying both sides by 8. Now we get (5n+1)=2(3n-5).

We then expand everything and get 5n+1=6n-10,

this turns into... what?

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