A AGlas9837 Junior Member Joined Jan 23, 2008 Messages 57 Jan 26, 2008 #1 The objective of this problem is to find the sales necessary to break even for the given cost and revenue equations. Cost = 5.5sqrt(x) + 10,000; Revenue = 3.29x This is what I've done so far: 3.29x = 5.5sqrt(x) + 10,000 3.29x-5.5sqrt(x) = 10,000 I'm stuck after this, not understanding how to substract the 5.5 square root part.

The objective of this problem is to find the sales necessary to break even for the given cost and revenue equations. Cost = 5.5sqrt(x) + 10,000; Revenue = 3.29x This is what I've done so far: 3.29x = 5.5sqrt(x) + 10,000 3.29x-5.5sqrt(x) = 10,000 I'm stuck after this, not understanding how to substract the 5.5 square root part.

stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 15,943 Jan 26, 2008 #2 AGlas9837 said: I'm stuck after this, not understanding how to substract the 5.5 square root part. Click to expand... To learn how to solve radical equations, please study some of the many great lessons available online: . . . . .Google results for "solving radical equations" Once you have studied some lessons (at least two!), please attempt the exercise. If you get stuck, or if you are unsure of your steps or solution, please reply clearly showing your work and reasoning. Thank you! Eliz.

AGlas9837 said: I'm stuck after this, not understanding how to substract the 5.5 square root part. Click to expand... To learn how to solve radical equations, please study some of the many great lessons available online: . . . . .Google results for "solving radical equations" Once you have studied some lessons (at least two!), please attempt the exercise. If you get stuck, or if you are unsure of your steps or solution, please reply clearly showing your work and reasoning. Thank you! Eliz.

P PAULK Junior Member Joined Dec 13, 2007 Messages 124 Jan 27, 2008 #3 AGlas9837 said: The objective of this problem is to find the sales necessary to break even for the given cost and revenue equations. Cost = 5.5sqrt(x) + 10,000; Revenue = 3.29x This is what I've done so far: 3.29x = 5.5sqrt(x) + 10,000 3.29x-5.5sqrt(x) = 10,000 I'm stuck after this, not understanding how to substract the 5.5 square root part. Click to expand... Try this: Let y = sqrt(x). Then x = y^2. You now have: 3.29y^2 - 5.5y = 10000, a quadratic equation.

AGlas9837 said: The objective of this problem is to find the sales necessary to break even for the given cost and revenue equations. Cost = 5.5sqrt(x) + 10,000; Revenue = 3.29x This is what I've done so far: 3.29x = 5.5sqrt(x) + 10,000 3.29x-5.5sqrt(x) = 10,000 I'm stuck after this, not understanding how to substract the 5.5 square root part. Click to expand... Try this: Let y = sqrt(x). Then x = y^2. You now have: 3.29y^2 - 5.5y = 10000, a quadratic equation.