Calculating probability for both teams to score in a soccer match

Anst

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Dear reader,
I have searched the net for hours regarding this question but I'm still not sure that I do it right.

My question is simple:
Team A scores in 75% of their matches. Team B scores in 65 % of their matches. How do I calculate the probability of both teams to score and/or that both teams will not score?

There is only one combination for the first outcome but three for the second which really confuses me (Team A yes Team B no, Team A no Team B yes, and Team A no and Team B no.

Thank you in advance if someone are that helpful!
 
Team A scores in 75% of their matches. Team B scores in 65 % of their matches. How do I calculate the probability of both teams to score and/or that both teams will not score?

There is only one combination for the first outcome but three for the second which really confuses me (Team A yes Team B no, Team A no Team B yes, and Team A no and Team B no.
If your book has not provided a definition for "and/or", then I would take this as meaning "non-exclusive or". In other words, the question is asking "What is the probability that either both teams do score or that both teams do not score?"

(The question is poorly worded, I agree. Your best best would be to ask your instructor for clarification.)
 
If your book has not provided a definition for "and/or", then I would take this as meaning "non-exclusive or". In other words, the question is asking "What is the probability that either both teams do score or that both teams do not score?"

(The question is poorly worded, I agree. Your best best would be to ask your instructor for clarification.)

If you know the probability that both teams will score then I guess you know the probability of both teams will not to score. So again, what is the probability that both teams will score if team A scores in 75% of their matches and team B scores in 65 % of their matches? How is it calculated?
Thanks.
 
Dear reader,
I have searched the net for hours regarding this question but I'm still not sure that I do it right.

My question is simple:
Team A scores in 75% of their matches. Team B scores in 65 % of their matches. How do I calculate the probability of both teams to score and/or that both teams will not score?

There is only one combination for the first outcome but three for the second which really confuses me (Team A yes Team B no, Team A no Team B yes, and Team A no and Team B no.

Thank you in advance if someone are that helpful!

Either the event will happen [Team A scores, probability a] or does not happen [Team A does not score, probability 1-a]. Same with Team B. Assuming the events are independent [except possibly when they play each other] we have, using + for does score and - for doesn't score,
Code:
+A+B  = a b
+A-B  = a (1-b)
-A-B  = (1-a) (1-b)
-A+B  = (1-a) b
 
Either the event will happen [Team A scores, probability a] or does not happen [Team A does not score, probability 1-a]. Same with Team B. Assuming the events are independent [except possibly when they play each other] we have, using + for does score and - for doesn't score,
Code:
+A+B  = a b
+A-B  = a (1-b)
-A-B  = (1-a) (1-b)
-A+B  = (1-a) b

Thanks a lot!
 
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