W Wilco6a New member Joined Oct 23, 2013 Messages 2 Oct 23, 2013 #1 I think I am over thinking this one: 1/2x^{2} = 1/x - 1/2

S srmichael Full Member Joined Oct 25, 2011 Messages 848 Oct 23, 2013 #2 Wilco6a said: I think I am over thinking this one: 1/2x^{2} = 1/x - 1/2 Click to expand... Well, first, is it \(\displaystyle \dfrac{1}{2}x^2 = \dfrac{1}{x}-\dfrac{1}{2} ...or... \dfrac{1}{2x^2} = \dfrac{1}{x}-\dfrac{1}{2}\)

Wilco6a said: I think I am over thinking this one: 1/2x^{2} = 1/x - 1/2 Click to expand... Well, first, is it \(\displaystyle \dfrac{1}{2}x^2 = \dfrac{1}{x}-\dfrac{1}{2} ...or... \dfrac{1}{2x^2} = \dfrac{1}{x}-\dfrac{1}{2}\)

W Wilco6a New member Joined Oct 23, 2013 Messages 2 Oct 23, 2013 #3 Sorry, its the 1st one. I'm writing on my phone so couldn't show the equation. correctly.

S srmichael Full Member Joined Oct 25, 2011 Messages 848 Oct 23, 2013 #4 So you say you may be overthinking this one. Please share your thoughts with us so we can see if that is the case.

So you say you may be overthinking this one. Please share your thoughts with us so we can see if that is the case.