passionflower_40
New member
- Joined
- Oct 8, 2005
- Messages
- 43
Find two numbers whose sum is 48 and such that one is 3 times as large as the other.
(We will call the two numbers x and y .)
(We will call the two numbers x and y .)
tkhunny said:passionflower_40,
You don't seem to be getting anywhere. You wrote definitions on this one, but have taken no additional step. Practice doing the whole problem.
Definitions:
x = one of the numbers
y = the other number
Translate the Problem Statement
"two numbers whose sum is 48"
What does that mean in terms of the two numbers, x and y? What is a "sum"?
"one is 3 times as large as the other"
What does that mean in terms of the two numbers, x and y? What does "3 times" mean?
Let's see what you get.
passionflower_40 said:9 is 3 times greater than 6. can you please check my answer.
Denis said:passionflower_40 said:9 is 3 times greater than 6. can you please check my answer.
Better get this straight, flower, else you'll keep having problems:
9 is NOT 3 times greater than 6: 9 is greater than 6 by 3: 9 - 6 = 3
Remember that the sum of the two numbers is what you get when you add those two numbers.
The sum of x and y is 48. How do we write an equation for that?