# Can someone help with this exercise? stuck on a probabily silly part

#### ferrika3

##### New member
Hello!
I have to complete an assignment and one of the exercises says:

I have been working on it for a while and i always get a 1/4 too much, is it solvable or can it be an error of the text?
this is what i get:

Thank you so much for your time and help

#### Jomo

##### Elite Member
Your 3rd line is not correct. Try again and post back your results

#### lex

##### Full Member
$$\displaystyle \frac{dy}{du}=4u^3\quad$$ (not $$\displaystyle u^3$$)

#### ferrika3

##### New member
Thank you all for the help, I am sorry for the late answer but work got in the way. Here's the corrected version which hopefully should be correct.

#### lex

##### Full Member
That's it. (With x≥1, y≥0 assuming Real numbers).

Thank you!

You're welcome.