Can you help me?? Frustrating Prob yo.

thisyearsdude

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Joined
Sep 13, 2005
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How many quarts of a pure solution must be added to 5% solution to get 4 quarts of a 14.5% solution ??




thnx for any solutions.
 
Why is this posted to calculus...?

Using algebraic methods:

. . . . .quarts solution:
. . . . .5%: x
. . . . .pure: 4 - x
. . . . .mix: 4

. . . . .percent solute:
. . . . .5%: 0.05
. . . . .pure: 1
. . . . .mix: 0.04

. . . . .quarts solute:
. . . . .5%: 0.05(x)
. . . . .pure: ...?
. . . . .mix: ...?

Add the inputs, set equal to the output, and solve.

Eliz.
 
Let x be the amount of pure solution

then you will have (4-x) of the 5% solution

(100%) x + (5%) (4-x) = (14.5%) (4)

x +0.05 (4-x) =0.145 (4)

solve for x.....
 
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